Since it opposes the current flow, it slows the current flow. In addition, my prediction that doubling the length of the wire increases the resistance by a factor of two is correct see Table 4. Large conductors allow more current flow and less voltage, that means less resistance and thin conductors allow less current flow and thus more resistance.
The temperature coefficient of resistance of many pure metals is close to 0. I will then turn the power pack on and record what voltmeter and ammeter readings.
The water should be kept very well stirred. My data collection was rational to the hypothesis and the research question. In addition, I will make sure I turn the power pack off after each reading.
Use the widget below to determine the resistance value from the colored stripes. Noon This investigation determine whether changing the length of the wire affects the resistance of the wire, thus experimenting on different length of the wires therefore becomes an independent variable.
This was because I could plot a graph and show the general trend. Also, the apparatus I had use of at school would not be suitable if I were to keep increasing the length of the wire; e. Resistance from the graph Formula: The fiberglass surrounded a glass tube.
The graph represents the verification of the battery eliminator Varifying the Battery eliminator 12 10 8 Voltage through Voltage the battery 6 eliminator 4 2 0 0 2 4 6 8 10 12 voltage in the battery Eliminator The graph above represents the voltage through the battery eliminator to check if the battery eliminator is accurate or not.
In either case, different wires should be made of the same material. During this time the coil heats up and the current changes quite rapidly. This discharges the cell rapidly and can make it explode. The resistance of a piece of wire is 1 ohm if a current of 1 A flows through it when a voltage of 1 V is applied between its ends.
Investigating the changing resistance of a wire as it heats up. Write up your experiment fully. Use the Resistivity of a Material widget to look up the resistivity of a given material. Explain that the resistance of the wire is equal to p.
The coil should be loosely wound from 1 m of polyurethane-coated copper wire 30 or 33 SWG. Variables How will I control them? The coil should be loosely wound from 1 m of polyurethane-coated copper wire 30 or 33 SWG. Students will find it easier to measure at a prescribed length if they tape the wire to a metre rule with insulating tape and make connections with flying leads rather than crocodile clips.
Resistance is inversely proportional to current. Even when the investigation was challenging, I used various skills and developed them as well, it was indeed a learning experience.
A V Circuit one: One approach is as discussed above to keep the wire at a constant temperature by immersing it in a water bath.The measured resistance will vary directly with the distance.
The electrical resistivity is an intrinsic property and should therefore be independent of length and cross-sectional area, but in this activity. search essay examples. browse by category. browse by type. Get Expert. An Experiment to Determine Resistance in Relation to a Wire's Length.
2 pages. An Introduction to the Dependant Variable and the Resistance of the Wire. 1, words. 3 pages. An Experiment to Measure Wire Resistance in Relation to Changing.
Extended experimental investigation: Electricity relationship between length and resistance. Copper wire of nominal diameter not associated with the experiment were kept away (A Risk Assessment was completed in the original student work).
Method. 1. The ohmmeter was configured. Explain that the resistance of the wire is equal to p.d. divided by current; i.e. it is the gradient of the line from the origin to the point on the graph. Place a ruler on the graph, through the origin, and passing through the highest point on the graph.
Apr 19, · For example, when the length of the wire is 20cm the resistance is ohms; when the length of the wire is 40cm the resistance is ohms, which is roughly double. In my main investigation I will see if this observation applies to my bigskyquartet.coms: Explain that the resistance of the wire is equal to p.d.
divided by current; i.e. it is the gradient of the line from the origin to the point on the graph. Place a ruler on the graph, through the origin, and passing through the highest point on the graph.Download